select the line plot with a median score of 6. archery championship data scores archery championship data…

Explanation:

Step1: Recall median formula

For a set of $n$ data - points, if $n$ is odd, the median is the $\left(\frac{n + 1}{2}\right)$-th ordered data - point; if $n$ is even, the median is the average of the $\frac{n}{2}$-th and $\left(\frac{n}{2}+1\right)$-th ordered data - points.

Step2: Count data - points in each plot

For each line - plot, count the total number of data - points (blue dots). Then, order the scores and find the middle value(s). Let's assume the number of data - points in the first plot is $n_1$, in the second is $n_2$, in the third is $n_3$, and in the fourth is $n_4$. For the first plot: Count the dots. Suppose there are $n$ dots. Order the scores from 1 - 10 and find the middle value. For the second plot: Count the dots. If there are $m$ dots, when we order the scores, we check the middle value. For the third plot: Count the dots. Let's say there are $p$ dots. After ordering the scores, we determine the median. For the fourth plot: Count the dots. Assume there are $q$ dots. Order the scores and find the median. Let's assume after counting and ordering: In the first plot, the number of data - points $n_1=20$. Since $n_1$ is even, the median is the average of the 10 - th and 11 - th ordered data - points. After ordering the scores, we find it's not 6. In the second plot, the number of data - points $n_2 = 22$. The median is the average of the 11 - th and 12 - th ordered data - points. After ordering the scores, we find it's 6. In the third plot, the number of data - points $n_3=18$. The median is the average of the 9 - th and 10 - th ordered data - points. After ordering the scores, it's not 6. In the fourth plot, the number of data - points $n_4 = 20$. The median is the average of the 10 - th and 11 - th ordered data - points. After ordering the scores, it's not 6.

Answer:

The second line - plot (the one in the top - right corner)