a set of average city temperatures in december are normally distributed with a mean of 16.3°c and a standard…

a set of average city temperatures in december are normally distributed with a mean of 16.3°c and a standard deviation of 2°c. what proportion of temperatures are between 12.9°c and 14.9°c? you may round your answer to four decimal places.
Answer
Explanation:
Step1: Calculate z - scores
The formula for the z - score is $z=\frac{x-\mu}{\sigma}$, where $\mu$ is the mean, $\sigma$ is the standard deviation, and $x$ is the value from the data - set. For $x = 12.9$, $z_1=\frac{12.9 - 16.3}{2}=\frac{- 3.4}{2}=-1.7$. For $x = 14.9$, $z_2=\frac{14.9 - 16.3}{2}=\frac{-1.4}{2}=-0.7$.
Step2: Use the standard normal distribution table
We want to find $P(-1.7<Z<-0.7)$. We know that $P(-1.7<Z<-0.7)=P(Z < - 0.7)-P(Z < - 1.7)$. From the standard - normal distribution table, $P(Z < - 0.7)=0.2420$ and $P(Z < - 1.7)=0.0446$.
Step3: Calculate the probability
$P(-1.7<Z<-0.7)=0.2420 - 0.0446=0.1974$.
Answer:
$0.1974$