sheila does quality control for a company that manufactures lawn mower parts. on any given day, she finds…

sheila does quality control for a company that manufactures lawn mower parts. on any given day, she finds the probability distribution for defective parts as shown in the table. using the data from the table, what is the probability of having 2 defective parts in a day? what is the probability that on a given day there, sheila will find defects? defective parts: x probability: p(x) 0 0.85 1 0.10 2 0.04 3 0.01

sheila does quality control for a company that manufactures lawn mower parts. on any given day, she finds the probability distribution for defective parts as shown in the table. using the data from the table, what is the probability of having 2 defective parts in a day? what is the probability that on a given day there, sheila will find defects? defective parts: x probability: p(x) 0 0.85 1 0.10 2 0.04 3 0.01

Answer

Explanation:

Step1: Define the event

The event of finding defects means having 1, 2, or 3 defective parts.

Step2: Use the addition - rule of probability

The probability of finding defects $P(X\geq1)$ is $P(X = 1)+P(X = 2)+P(X = 3)$. We know that $P(X = 1)=0.10$, $P(X = 2)=0.04$ and $P(X = 3)=0.01$. So $P(X\geq1)=0.10 + 0.04+0.01$.

Step3: Calculate the result

$P(X\geq1)=0.15$.

Answer:

0.15