a six - sided number cube is rolled twice. which expression can be used to find p(5, then3)?\no…

a six - sided number cube is rolled twice. which expression can be used to find p(5, then3)?\no $\frac{1}{5}cdot\frac{1}{3}$\no $\frac{1}{6}cdot\frac{1}{5}$\no $\frac{5}{6}cdot\frac{3}{6}$\no $\frac{1}{6}cdot\frac{1}{6}$

a six - sided number cube is rolled twice. which expression can be used to find p(5, then3)?\no $\frac{1}{5}cdot\frac{1}{3}$\no $\frac{1}{6}cdot\frac{1}{5}$\no $\frac{5}{6}cdot\frac{3}{6}$\no $\frac{1}{6}cdot\frac{1}{6}$

Answer

Explanation:

Step1: Probability of rolling a 5

The probability of rolling a 5 on a six - sided number cube is $\frac{1}{6}$ since there is 1 favorable outcome (rolling a 5) out of 6 possible outcomes (numbers 1 - 6).

Step2: Probability of rolling a 3

The probability of rolling a 3 on a six - sided number cube is $\frac{1}{6}$ since there is 1 favorable outcome (rolling a 3) out of 6 possible outcomes (numbers 1 - 6).

Step3: Probability of both events

Since the two rolls are independent events, the probability of rolling a 5 first and then a 3 is the product of their individual probabilities. So $P(5,\text{ then }3)=\frac{1}{6}\times\frac{1}{6}$.

Answer:

D. $\frac{1}{6}\cdot\frac{1}{6}$