6. the spinner below is spun twice. what is the probability of the arrow landing on a white space and then a…

Explanation:

Step1: Determine total sections

The spinner is divided into 6 equal - sized sections. So the total number of possible outcomes for each spin is 6.

Step2: Find probability of landing on white

There are 2 white - colored sections. The probability of landing on a white space on the first spin, $P(W)=\frac{2}{6}=\frac{1}{3}$.

Step3: Find probability of landing on star - space

There are 3 sections with stars. The probability of landing on a space with stars on the second spin, $P(S)=\frac{3}{6}=\frac{1}{2}$.

Step4: Use multiplication rule for independent events

Since the two spins are independent events, the probability of both events occurring is the product of their individual probabilities. $P = P(W)\times P(S)$. $P=\frac{1}{3}\times\frac{1}{2}=\frac{1}{6}$.

Answer:

$\frac{1}{6}$