a standard deck of 52 cards contains 13 cards with hearts, 13 with diamonds, 13 with clubs, and 13 with…

a standard deck of 52 cards contains 13 cards with hearts, 13 with diamonds, 13 with clubs, and 13 with spades. how many 7 - card hands are possible with 2 hearts, 2 diamonds, 2 clubs, and 1 spade? assume that the order of the cards does not matter, and use the formula for combinations to find your answer.\n474,552\n6,169,176\n49,353,408\n133,784,560
Answer
Answer:
B. 6,169,176
Explanation:
Step1: Recall combination formula
The combination formula is $C(n,r)=\frac{n!}{r!(n - r)!}$, where $n$ is the total number of items and $r$ is the number of items to be chosen.
Step2: Calculate number of ways to choose hearts
For hearts, $n = 13$ and $r=2$. So $C(13,2)=\frac{13!}{2!(13 - 2)!}=\frac{13\times12}{2\times1}=78$.
Step3: Calculate number of ways to choose diamonds
For diamonds, $n = 13$ and $r = 2$. So $C(13,2)=\frac{13!}{2!(13 - 2)!}=\frac{13\times12}{2\times1}=78$.
Step4: Calculate number of ways to choose clubs
For clubs, $n = 13$ and $r = 2$. So $C(13,2)=\frac{13!}{2!(13 - 2)!}=\frac{13\times12}{2\times1}=78$.
Step5: Calculate number of ways to choose spades
For spades, $n = 13$ and $r = 1$. So $C(13,1)=\frac{13!}{1!(13 - 1)!}=13$.
Step6: Calculate total number of 7 - card hands
By the multiplication principle, the total number of 7 - card hands is $C(13,2)\times C(13,2)\times C(13,2)\times C(13,1)=78\times78\times78\times13 = 6169176$.