for a standard normal distribution, find the approximate value of p(z≥ - 1.25). use the portion of the…

for a standard normal distribution, find the approximate value of p(z≥ - 1.25). use the portion of the standard normal table below to help answer the question.\n| z | probability |\n| ---- | ---- |\n| 0.00 | 0.5000 |\n| 0.25 | 0.5987 |\n| 1.00 | 0.8413 |\n| 1.25 | 0.8944 |\n| 1.50 | 0.9332 |\n| 1.75 | 0.9599 |\n\n11%\n39%\n61%\n89%

for a standard normal distribution, find the approximate value of p(z≥ - 1.25). use the portion of the standard normal table below to help answer the question.\n| z | probability |\n| ---- | ---- |\n| 0.00 | 0.5000 |\n| 0.25 | 0.5987 |\n| 1.00 | 0.8413 |\n| 1.25 | 0.8944 |\n| 1.50 | 0.9332 |\n| 1.75 | 0.9599 |\n\n11%\n39%\n61%\n89%

Answer

Explanation:

Step1: Recall property of normal distribution

The total area under the standard - normal curve is 1. Also, $P(Z\geq z)=1 - P(Z < z)$.

Step2: Find $P(Z < - 1.25)$

The standard - normal table gives $P(Z < 1.25)=0.8944$. Since the standard - normal distribution is symmetric about $z = 0$, $P(Z < - 1.25)=1 - P(Z < 1.25)$. So $P(Z < - 1.25)=1 - 0.8944 = 0.1056$.

Step3: Calculate $P(Z\geq - 1.25)$

Using the formula $P(Z\geq - 1.25)=1 - P(Z < - 1.25)$. Substitute $P(Z < - 1.25)=0.1056$ into the formula, we get $P(Z\geq - 1.25)=1 - 0.1056=0.8944\approx89%$.

Answer:

89%