in a standard normal distribution, 1.5% of observations lie above which z - score? find the z - table here…

in a standard normal distribution, 1.5% of observations lie above which z - score? find the z - table here. -2.17 -1.03 1.03 2.17
Answer
Explanation:
Step1: Convert percentage to proportion
If 1.5% of observations lie above a z - score, then the proportion of observations above the z - score is $p = 0.015$. The proportion of observations below the z - score is $1 - 0.015=0.985$.
Step2: Use the z - table
We look up the value 0.985 in the body of the standard normal (z -) table. The z - score corresponding to a cumulative probability of 0.985 is approximately 2.17.
Answer:
D. 2.17