in a standard normal distribution, what percentage of observations lie above z = 0.16? find the z - table…
in a standard normal distribution, what percentage of observations lie above z = 0.16? find the z - table here. 14.46% 43.64% 56.36% 85.54%
Answer
Explanation:
Step1: Understand z - table usage
The z - table gives the cumulative probability $P(Z\leq z)$. For $z = 0.16$, we look up the value in the standard normal z - table.
Step2: Find cumulative probability
From the z - table, $P(Z\leq0.16)=0.5636$.
Step3: Calculate probability above z = 0.16
We know that $P(Z > z)=1 - P(Z\leq z)$. So $P(Z > 0.16)=1 - 0.5636 = 0.4364$.
Step4: Convert to percentage
To convert the probability to a percentage, we multiply by 100. So $0.4364\times100 = 43.64%$.
Answer:
43.64%