for a standard normal distribution, if $p(zleq a)=0.7116$, what is the value of $p(zgeq a)$?\n0.2116\n0.2884\…

for a standard normal distribution, if $p(zleq a)=0.7116$, what is the value of $p(zgeq a)$?\n0.2116\n0.2884\n0.7116\n0.7884

for a standard normal distribution, if $p(zleq a)=0.7116$, what is the value of $p(zgeq a)$?\n0.2116\n0.2884\n0.7116\n0.7884

Answer

Explanation:

Step1: Recall total probability rule

The total probability under the standard - normal curve is 1. That is, (P(Z\leq a)+P(Z\geq a) = 1).

Step2: Solve for (P(Z\geq a))

We know (P(Z\leq a)=0.7116). Rearranging the formula (P(Z\geq a)=1 - P(Z\leq a)). Substitute (P(Z\leq a) = 0.7116) into the formula: (P(Z\geq a)=1 - 0.7116=0.2884).

Answer:

0.2884