on a standardized exam, the scores are normally distributed with a mean of 300 and a standard deviation of…

on a standardized exam, the scores are normally distributed with a mean of 300 and a standard deviation of 20. find the z - score of a person who scored 295 on the exam.
Answer
Explanation:
Step1: Recall z - score formula
The z - score formula is $z=\frac{x-\mu}{\sigma}$, where $x$ is the value from the data set, $\mu$ is the mean, and $\sigma$ is the standard deviation.
Step2: Identify values
We are given that $\mu = 300$, $\sigma=20$, and $x = 295$.
Step3: Substitute values into formula
$z=\frac{295 - 300}{20}=\frac{- 5}{20}=-0.25$
Answer:
$-0.25$