a student incorrectly measured the volume of a mineral sample as 63 cubic centimeters. the actual volume was…

a student incorrectly measured the volume of a mineral sample as 63 cubic centimeters. the actual volume was 72 cubic centimeters. what was the students approximate percent deviation (percentage of error)?\n1. 9.0%\n2. 12.5%\n3. 14.2%\n4. 15.3%
Answer
Explanation:
Step1: Calculate the error
Error = |Measured value - Actual value| = |63 - 72| = 9
Step2: Calculate percent - deviation
Percent - deviation = $\frac{\text{Error}}{\text{Actual value}}\times100%=\frac{9}{72}\times100%$ $=\frac{1}{8}\times100% = 12.5%$
Answer:
- 12.5%