the students in marlys math class recorded the dimensions of their bedrooms in a frequency table. bedroom…

the students in marlys math class recorded the dimensions of their bedrooms in a frequency table. bedroom areas area (sq. ft) number of bedrooms 60≤a<80 4 80≤a<100 6 100≤a<120 5 120≤a<140 3 140≤a<160 1 create a histogram to represent the data. which statement is most likely true about the mean and the median of the data? the histogram is right - skewed, so the mean is less than the median. the histogram is right - skewed, so the mean is greater than the median. the histogram is left - skewed, so the mean is less than the median. the histogram is left - skewed, so the mean is greater than the median.

the students in marlys math class recorded the dimensions of their bedrooms in a frequency table. bedroom areas area (sq. ft) number of bedrooms 60≤a<80 4 80≤a<100 6 100≤a<120 5 120≤a<140 3 140≤a<160 1 create a histogram to represent the data. which statement is most likely true about the mean and the median of the data? the histogram is right - skewed, so the mean is less than the median. the histogram is right - skewed, so the mean is greater than the median. the histogram is left - skewed, so the mean is less than the median. the histogram is left - skewed, so the mean is greater than the median.

Answer

Explanation:

Step1: Analyze skewness

As the frequencies decrease from the lower - class intervals to the higher - class intervals ($4,6,5,3,1$), the histogram will be right - skewed.

Step2: Recall skewness and mean - median relationship

In a right - skewed distribution, the tail on the right side pulls the mean in that direction. So, the mean is greater than the median.

Answer:

The histogram is right - skewed, so the mean is greater than the median.