the students in marlys math class recorded the dimensions of their bedrooms in a frequency table. bedroom…

the students in marlys math class recorded the dimensions of their bedrooms in a frequency table. bedroom areas\narea (sq. ft) number of bedrooms\n60 ≤ a < 80 4\n80 ≤ a < 100 6\n100 ≤ a < 120 5\n120 ≤ a < 140 3\n140 ≤ a < 160 1\ncreate a histogram to represent the data. which statement is most likely true about the mean and the median of the data?\nthe histogram is right - skewed, so the mean is less than the median.\nthe histogram is right - skewed, so the mean is greater than the median.\nthe histogram is left - skewed, so the mean is less than the median.\nthe histogram is left - skewed, so the mean is greater than the median.

the students in marlys math class recorded the dimensions of their bedrooms in a frequency table. bedroom areas\narea (sq. ft) number of bedrooms\n60 ≤ a < 80 4\n80 ≤ a < 100 6\n100 ≤ a < 120 5\n120 ≤ a < 140 3\n140 ≤ a < 160 1\ncreate a histogram to represent the data. which statement is most likely true about the mean and the median of the data?\nthe histogram is right - skewed, so the mean is less than the median.\nthe histogram is right - skewed, so the mean is greater than the median.\nthe histogram is left - skewed, so the mean is less than the median.\nthe histogram is left - skewed, so the mean is greater than the median.

Answer

Explanation:

Step1: Analyze skewness

As the frequency decreases as the area increases (4, 6, 5, 3, 1 for increasing area intervals), the histogram will be right - skewed.

Step2: Recall mean - median relationship for skewed data

In a right - skewed distribution, the tail on the right (higher values) pulls the mean in that direction. So the mean is greater than the median.

Answer:

The histogram is right - skewed, so the mean is greater than the median.