suppose that 71% of the surface of the earth is covered in water, and a random number generator uses…

suppose that 71% of the surface of the earth is covered in water, and a random number generator uses latitude and longitude to select a random location on the earth. if 6 locations are generated, what is the probability that at least 1 of those locations is over land?\n0.0006\n0.1281\n0.8719\n0.9994

suppose that 71% of the surface of the earth is covered in water, and a random number generator uses latitude and longitude to select a random location on the earth. if 6 locations are generated, what is the probability that at least 1 of those locations is over land?\n0.0006\n0.1281\n0.8719\n0.9994

Answer

Explanation:

Step1: Find probability of water - covered location

The probability that a location is covered in water is $p = 0.71$.

Step2: Find probability that all 6 locations are water - covered

Using the binomial probability formula $P(X = k)=C(n,k)\times p^{k}\times(1 - p)^{n - k}$, where $n = 6$, $k = 6$, and $p = 0.71$. Since $C(6,6)=1$, the probability that all 6 locations are water - covered is $P(X = 6)=0.71^{6}$. $0.71^{6}=0.71\times0.71\times0.71\times0.71\times0.71\times0.71\approx0.0006$.

Step3: Find probability that at least 1 location is over land

The probability that at least 1 location is over land is the complement of the event that all locations are covered in water. Let $A$ be the event that at least 1 location is over land, and $B$ be the event that all locations are covered in water. Then $P(A)=1 - P(B)$. $P(A)=1 - 0.71^{6}\approx1 - 0.0006 = 0.9994$.

Answer:

0.9994