suppose that the frequency table below contains data on male life expectancy at birth in 79 randomly…
suppose that the frequency table below contains data on male life expectancy at birth in 79 randomly selected countries. click to download the data in your preferred format. crunchit! csv excel jmp mac text minitab pc text r spss ti calc use the table to determine the median life expectancy for males in these 79 countries. median = years
Answer
Explanation:
Step1: Calculate cumulative frequencies
| Age | Frequency | Cumulative Frequency |
|---|---|---|
| 74 | 25 | 25 |
| 75 | 16 | 25 + 16=41 |
| 76 | 10 | 41+ 10 = 51 |
| 77 | 11 | 51+11 = 62 |
| 78 | 5 | 62 + 5=67 |
| 79 | 4 | 67+4 = 71 |
| 80 | 3 | 71+3 = 74 |
| 81 | 2 | 74+2 = 76 |
| 82 | 3 | 76+3 = 79 |
Step2: Find the position of the median
Since (n = 79) (an odd - numbered data set), the position of the median is (\frac{n + 1}{2}=\frac{79+1}{2}=40)
Step3: Determine the median value
The cumulative frequency just greater than or equal to 40 is 41, and the corresponding age value is 75.
Answer:
75