suppose a normal distribution has a mean of 12 and a standard deviation of 4. a value of 18 is how many…

Explanation:

Step1: Identify the formula

The formula for the z - score (number of standard deviations from the mean) is $z=\frac{x - \mu}{\sigma}$, where $x$ is the value, $\mu$ is the mean, and $\sigma$ is the standard deviation.

Step2: Substitute the given values

We have $x = 18$, $\mu=12$, and $\sigma = 4$. So $z=\frac{18 - 12}{4}$.

Step3: Calculate the z - score

$\frac{18 - 12}{4}=\frac{6}{4}=1.5$.

Answer:

C. 1.5