suppose that the random variable x, shown below, represents the number of speeding tickets a person received…

suppose that the random variable x, shown below, represents the number of speeding tickets a person received in a three - year period. p(x) represents the probability of a randomly selected person having received that number of speeding tickets during that period. use the probability distribution table shown below to answer the following questions.\n|x|p(x)|\n|0|0.3034|\n|1|0.2626|\n|2|0.2211|\n|3|0.1458|\n|4|0.0477|\n|5|0.0194|\n|6+|0.0000|\na) what is the probability that a randomly selected person has received four tickets in a three - year period? p(x = 4)=\n\nb) what is the probability that a randomly selected person has received four or more tickets in a three - year period? p(x≥4)=\n\nc) what is the probability that a randomly selected person has received more than four tickets in a three - year period? p(x > 4)=\n\nquestion help: message instructor post to forum

suppose that the random variable x, shown below, represents the number of speeding tickets a person received in a three - year period. p(x) represents the probability of a randomly selected person having received that number of speeding tickets during that period. use the probability distribution table shown below to answer the following questions.\n|x|p(x)|\n|0|0.3034|\n|1|0.2626|\n|2|0.2211|\n|3|0.1458|\n|4|0.0477|\n|5|0.0194|\n|6+|0.0000|\na) what is the probability that a randomly selected person has received four tickets in a three - year period? p(x = 4)=\n\nb) what is the probability that a randomly selected person has received four or more tickets in a three - year period? p(x≥4)=\n\nc) what is the probability that a randomly selected person has received more than four tickets in a three - year period? p(x > 4)=\n\nquestion help: message instructor post to forum

Answer

Explanation:

Step1: Find probability for $x = 4$

From the table, when $x = 4$, $P(x=4)=0.0477$.

Step2: Find probability for $x\geq4$

$P(x\geq4)=P(x = 4)+P(x = 5)+P(x\geq6)$. Since $P(x\geq6)=0.0000$, then $P(x\geq4)=0.0477 + 0.0194+0.0000=0.0671$.

Step3: Find probability for $x>4$

$P(x > 4)=P(x = 5)+P(x\geq6)$. Since $P(x\geq6)=0.0000$, then $P(x > 4)=0.0194+0.0000 = 0.0194$.

Answer:

a) $0.0477$ b) $0.0671$ c) $0.0194$