suppose that e and f are two events and that n(e and f) = 490 and n(e) = 860. what is p(f|e)?\np(f|e) ≈…

Explanation:

Step1: Recall the formula for conditional probability

The formula for conditional probability is $P(F|E)=\frac{P(E\cap F)}{P(E)}$. In terms of number of elements, if $N(E)$ is the number of elements in event $E$ and $N(E\cap F)$ is the number of elements in $E\cap F$, then $P(F|E)=\frac{N(E\cap F)}{N(E)}$.

Step2: Substitute the given values

We are given that $N(E\cap F) = 490$ and $N(E)=860$. Substituting these values into the formula, we get $P(F|E)=\frac{490}{860}$.

Step3: Calculate the result and round

$\frac{490}{860}\approx0.570$

Answer:

$0.570$