suppose you spin the spinner twice. what is the probability of spinning a green, then yellow? p(green…

suppose you spin the spinner twice. what is the probability of spinning a green, then yellow? p(green, yellow) = 1/? show your answer as a fraction in lowest terms. enter the denominator.

suppose you spin the spinner twice. what is the probability of spinning a green, then yellow? p(green, yellow) = 1/? show your answer as a fraction in lowest terms. enter the denominator.

Answer

Explanation:

Step1: Calculate probability of green

The spinner is divided into 8 equal - sized sections, and 3 are green. So the probability of spinning a green on the first spin, $P(G)=\frac{3}{8}$.

Step2: Calculate probability of yellow

After the first spin, the probabilities remain the same for the second spin. There is 1 yellow section out of 8, so the probability of spinning a yellow on the second spin, $P(Y)=\frac{1}{8}$.

Step3: Use multiplication rule for independent events

Since the two spins are independent events, the probability of spinning a green then a yellow is $P(G,Y)=P(G)\times P(Y)=\frac{3}{8}\times\frac{1}{8}=\frac{3}{64}$.

Answer:

64