a survey asked about the number of people who eat breakfast almost every day (b) and the number of people…

a survey asked about the number of people who eat breakfast almost every day (b) and the number of people who buy cereal at least once a month (c). the results of the survey are shown in the venn diagram. given that a randomly chosen person eats breakfast almost everyday, what is the probability that the person also buys cereal at least once a month? 11/64 11/53 53/64 53/57

a survey asked about the number of people who eat breakfast almost every day (b) and the number of people who buy cereal at least once a month (c). the results of the survey are shown in the venn diagram. given that a randomly chosen person eats breakfast almost everyday, what is the probability that the person also buys cereal at least once a month? 11/64 11/53 53/64 53/57

Answer

Answer:

$\frac{53}{64}$

Explanation:

Step1: Identify relevant numbers

Number of people who eat breakfast almost every day ($n(B)$) is $11 + 53=64$.

Step2: Identify intersection number

Number of people who eat breakfast almost every day and buy cereal at least once a month ($n(B\cap C)$) is $53$.

Step3: Apply conditional - probability formula

The formula for conditional probability $P(C|B)=\frac{n(B\cap C)}{n(B)}$. Substituting the values, we get $P(C|B)=\frac{53}{64}$.