a survey asked about the number of people who eat breakfast almost every day (b) and the number of people…

a survey asked about the number of people who eat breakfast almost every day (b) and the number of people who buy cereal at least once a month (c). the results of the survey are shown in the venn diagram. given that a randomly - chosen person eats breakfast almost everyday, what is the probability that the person also buys cereal at least once a month? 11/64 11/53 53/64 53/57

a survey asked about the number of people who eat breakfast almost every day (b) and the number of people who buy cereal at least once a month (c). the results of the survey are shown in the venn diagram. given that a randomly - chosen person eats breakfast almost everyday, what is the probability that the person also buys cereal at least once a month? 11/64 11/53 53/64 53/57

Answer

Answer:

D. $\frac{53}{57}$

Explanation:

Step1: Identify relevant numbers

The number of people who eat breakfast almost every day is $11 + 53=57$. The number of people who eat breakfast almost every day and buy cereal at least once a month is $53$.

Step2: Use conditional - probability formula

The formula for conditional probability $P(C|B)=\frac{P(B\cap C)}{P(B)}$. In terms of counts, if $n(B)$ is the number of people in event $B$ and $n(B\cap C)$ is the number of people in $B\cap C$, then $P(C|B)=\frac{n(B\cap C)}{n(B)}$. Here, $n(B\cap C) = 53$ and $n(B)=57$, so the probability is $\frac{53}{57}$.