a survey asked about the number of people who eat breakfast almost every day (b) and the number of people…

a survey asked about the number of people who eat breakfast almost every day (b) and the number of people who buy cereal at least once a month (c). the results of the survey are shown in the venn diagram. given that a randomly chosen person eats breakfast almost everyday, what is the probability that the person also buys cereal at least once a month? o $\frac{11}{64}$ o $\frac{11}{53}$ o $\frac{53}{64}$ o $\frac{53}{57}$

a survey asked about the number of people who eat breakfast almost every day (b) and the number of people who buy cereal at least once a month (c). the results of the survey are shown in the venn diagram. given that a randomly chosen person eats breakfast almost everyday, what is the probability that the person also buys cereal at least once a month? o $\frac{11}{64}$ o $\frac{11}{53}$ o $\frac{53}{64}$ o $\frac{53}{57}$

Answer

Answer:

$\frac{53}{64}$

Explanation:

Step1: Identify relevant values

We want $P(C|B)$. The number of people who eat breakfast almost every - day ($B$) is $11 + 53=64$. The number of people who eat breakfast almost every - day and buy cereal at least once a month ($B\cap C$) is $53$.

Step2: Apply conditional - probability formula

The formula for conditional probability is $P(C|B)=\frac{P(B\cap C)}{P(B)}$. In terms of counts, $P(C|B)=\frac{n(B\cap C)}{n(B)}$. Substituting $n(B\cap C) = 53$ and $n(B)=64$ into the formula, we get $P(C|B)=\frac{53}{64}$.