a survey asked about the number of people who eat breakfast almost every day (b) and the number of people…

a survey asked about the number of people who eat breakfast almost every day (b) and the number of people who buy cereal at least once a month (c). the results of the survey are shown in the venn - diagram. given that a randomly chosen person eats breakfast almost everyday, what is the probability that the person also buys cereal at least once a month? 11/64 11/53 53/64 53/57

a survey asked about the number of people who eat breakfast almost every day (b) and the number of people who buy cereal at least once a month (c). the results of the survey are shown in the venn - diagram. given that a randomly chosen person eats breakfast almost everyday, what is the probability that the person also buys cereal at least once a month? 11/64 11/53 53/64 53/57

Answer

Explanation:

Step1: Identify relevant numbers

We want $P(C|B)$. By the formula of conditional - probability $P(C|B)=\frac{P(B\cap C)}{P(B)}$. The number of people who eat breakfast almost every day $n(B)=11 + 53=64$. The number of people who eat breakfast almost every day and buy cereal at least once a month $n(B\cap C)=53$.

Step2: Calculate the probability

The probability $P(C|B)=\frac{n(B\cap C)}{n(B)}$. Substituting the values we found, we have $P(C|B)=\frac{53}{64}$.

Answer:

$\frac{53}{64}$