a survey was conducted at a high school to study pet ownership in different grade levels. the data gathered…

a survey was conducted at a high school to study pet ownership in different grade levels. the data gathered is in the two - way table below:\n| | dog | cat | no pet | total |\n|----|----|----|----|----|\n| freshman | 3 | 3 | 5 | 11 |\n| sophomore | 5 | 7 | 4 | 16 |\n| junior | 8 | 1 | 3 | 12 |\n| senior | 2 | 3 | 6 | 11 |\n| total | 18 | 14 | 18 | 50 |\nbased on this table, what is the relative frequency that a student is a freshman who has no pets?\n? %\nround your answer to the nearest hundredth.

a survey was conducted at a high school to study pet ownership in different grade levels. the data gathered is in the two - way table below:\n| | dog | cat | no pet | total |\n|----|----|----|----|----|\n| freshman | 3 | 3 | 5 | 11 |\n| sophomore | 5 | 7 | 4 | 16 |\n| junior | 8 | 1 | 3 | 12 |\n| senior | 2 | 3 | 6 | 11 |\n| total | 18 | 14 | 18 | 50 |\nbased on this table, what is the relative frequency that a student is a freshman who has no pets?\n? %\nround your answer to the nearest hundredth.

Answer

Explanation:

Step1: Identify relevant values

The number of fresh - men with no pets is 5, and the total number of students is 50.

Step2: Calculate relative frequency

The formula for relative frequency is $\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}$. So the relative frequency is $\frac{5}{50}= 0.1$.

Step3: Convert to percentage

To convert the decimal to a percentage, multiply by 100. So $0.1\times100 = 10.00%$.

Answer:

$10.00$