the table displays the scores of students on a recent exam. find the mean of the scores to the nearest 10th.

Explanation:

Step1: Calculate total score sum

$\begin{align*} &(65\times1)+(70\times6)+(75\times3)+(80\times4)+(85\times6)+(90\times7)+(95\times7)+(100\times5)\ =&65+420+225+320+510+630+665+500\ =&3335 \end{align*}$

Step2: Calculate total number of students

$1+6+3+4+6+7+7+5=39$

Step3: Compute the mean score

$\text{Mean}=\frac{3335}{39}\approx85.5128$

Step4: Round to nearest tenth

Round $85.5128$ to 1 decimal place.

Answer:

85.5