the table below gives the probability density for a particular bowl of candy.\ncolor brown red orange yellow…

the table below gives the probability density for a particular bowl of candy.\ncolor brown red orange yellow green blue\nprobability 0.13 0.13 0.20 0.14 0.16 0.24\nif a candy is drawn at random, what is the probability that it is red or green?\np = ?

the table below gives the probability density for a particular bowl of candy.\ncolor brown red orange yellow green blue\nprobability 0.13 0.13 0.20 0.14 0.16 0.24\nif a candy is drawn at random, what is the probability that it is red or green?\np = ?

Answer

Explanation:

Step1: Identify relevant probabilities

The probability of red candy $P(\text{Red}) = 0.13$, and the probability of green candy $P(\text{Green})=0.16$.

Step2: Use addition rule for mutually - exclusive events

Since a candy can't be both red and green at the same time (mutually - exclusive events), $P(\text{Red or Green})=P(\text{Red})+P(\text{Green})$. $P(\text{Red or Green})=0.13 + 0.16$

Answer:

$0.29$