the table below gives the probability density of taffies in a bag.\ntaffy banana chocolate cherry grape…

the table below gives the probability density of taffies in a bag.\ntaffy banana chocolate cherry grape vanilla\nprobability 0.21 0.19 0.16 0.13 0.31\nif a taffy is selected at random, what is the probability that it is a vanilla or banana?\nnow, enter the probability of banana.\np(banana) = ?

the table below gives the probability density of taffies in a bag.\ntaffy banana chocolate cherry grape vanilla\nprobability 0.21 0.19 0.16 0.13 0.31\nif a taffy is selected at random, what is the probability that it is a vanilla or banana?\nnow, enter the probability of banana.\np(banana) = ?

Answer

Explanation:

Step1: Identify given probabilities

The probability of banana - flavored taffy $P(\text{banana}) = 0.21$ and the probability of vanilla - flavored taffy $P(\text{vanilla}) = 0.31$.

Step2: Use addition rule for mutually - exclusive events

Since a taffy can't be both banana and vanilla at the same time (mutually - exclusive events), the probability of vanilla or banana $P(\text{vanilla or banana})=P(\text{vanilla})+P(\text{banana})$. $P(\text{vanilla or banana})=0.31 + 0.21=0.52$

Answer:

The probability that a randomly - selected taffy is vanilla or banana is $0.52$. The probability of banana is $0.21$.