the table below gives the probability density of trees in a particular park.\n| tree | birch | elm | oak |…

the table below gives the probability density of trees in a particular park.\n| tree | birch | elm | oak | pine | walnut |\n| probability | 0.19 | 0.04 | 0.34 | 0.17 | 0.26 |\nif a tree is selected at random, what is the probability that it is a birch or pine?\np = ?

the table below gives the probability density of trees in a particular park.\n| tree | birch | elm | oak | pine | walnut |\n| probability | 0.19 | 0.04 | 0.34 | 0.17 | 0.26 |\nif a tree is selected at random, what is the probability that it is a birch or pine?\np = ?

Answer

Answer:

$0.36$

Explanation:

Step1: Identify relevant probabilities

$P(\text{Birch}) = 0.19$, $P(\text{Pine})=0.17$

Step2: Use addition rule for mutually - exclusive events

$P(\text{Birch or Pine})=P(\text{Birch})+P(\text{Pine})$

Step3: Calculate the result

$P(\text{Birch or Pine})=0.19 + 0.17=0.36$