the table below gives the probability density of trees in a particular park.\n| tree | birch | elm | oak |…
the table below gives the probability density of trees in a particular park.\n| tree | birch | elm | oak | pine | walnut |\n| probability | 0.19 | 0.04 | 0.34 | 0.17 | 0.26 |\nif a tree is selected at random, what is the probability that it is an elm or oak?\np = ?
Answer
Explanation:
Step1: Identify relevant probabilities
The probability of an elm is $P(\text{Elm}) = 0.04$ and the probability of an oak is $P(\text{Oak}) = 0.34$.
Step2: Use addition rule for mutually - exclusive events
Since a tree can't be both an elm and an oak at the same time (mutually - exclusive events), the probability of an elm or oak is $P(\text{Elm or Oak})=P(\text{Elm}) + P(\text{Oak})$. $P(\text{Elm or Oak})=0.04 + 0.34$ $P(\text{Elm or Oak}) = 0.38$
Answer:
$0.38$