the table below shows the monthly expenses of a family. if the family decides to cut their entertainment…

the table below shows the monthly expenses of a family. if the family decides to cut their entertainment expense by 20%, how much will they save in a year?\nmonthly\nexpense amount ($)\nrent 1500\nfood 600\nutilities 300\nentertainment 200\n$575\n$520\n$350\n$725\nquestion 29 (3 points)\nif a data set is normally distributed with a mean of 200 and a standard deviation of 30, what is the z - score for a value of 140? $z=\frac{raw score - mean}{standard deviation}$\n-2.00\n-0.67\n-1.33\n-1.00\nquestion 30 (3 points)

the table below shows the monthly expenses of a family. if the family decides to cut their entertainment expense by 20%, how much will they save in a year?\nmonthly\nexpense amount ($)\nrent 1500\nfood 600\nutilities 300\nentertainment 200\n$575\n$520\n$350\n$725\nquestion 29 (3 points)\nif a data set is normally distributed with a mean of 200 and a standard deviation of 30, what is the z - score for a value of 140? $z=\frac{raw score - mean}{standard deviation}$\n-2.00\n-0.67\n-1.33\n-1.00\nquestion 30 (3 points)

Answer

Answer:

(1) First - part answer: Monthly entertainment expense is $200. A 20% cut means the monthly savings is $200\times0.2 = 40$. In a year (12 months), the savings is $40\times12=480$. But since this is not in the options, there may be an error in the problem - setup or options. Assuming we calculate it based on the options in a more 'round - off' way: Monthly entertainment expense = $200$. 20% of $200$ is $0.2\times200 = 40$. Annual savings = $40\times12 = 480$. If we assume some approximation in the calculation process in the context of the given options, we recalculate: Monthly savings from entertainment = $200\times0.2=40$. Annual savings = $40\times12 = 480$. None of the given options ($575,520,350,725$) are correct. (2) Second - part answer: Using the z - score formula $z=\frac{\text{raw score}-\text{mean}}{\text{standard deviation}}$. Here, the raw score is 140, the mean is 200, and the standard deviation is 30. $z=\frac{140 - 200}{30}=\frac{- 60}{30}=-2.00$

So the answers are: (1) None of the above (but if forced to choose based on closest approximation, there is an issue with the problem) (2) A. - 2.00