a textbook company states that the average time a student needs to take a quiz from its book is 30 minutes…

a textbook company states that the average time a student needs to take a quiz from its book is 30 minutes with a standard deviation of 3 minutes. a teacher using the book is not sure that this is correct for her classes and wants to check. she collects data on 10 random students and finds that the average time to take the quiz was only 25 minutes. as a result, the teacher performs a two - tailed hypothesis test with a significance level of 5%. which conclusion is valid based on the results of the test?\no her students, on average, do not take 30 minutes on the quiz, contrary to what the textbook company stated.\no the teacher should pick up all unfinished quizzes at 25 minutes because her students are so much faster than average.\no the teacher does not have enough information to make a conclusion about the average time on the test.\no her students, on average, do take the 30 minutes as the textbook company stated.

a textbook company states that the average time a student needs to take a quiz from its book is 30 minutes with a standard deviation of 3 minutes. a teacher using the book is not sure that this is correct for her classes and wants to check. she collects data on 10 random students and finds that the average time to take the quiz was only 25 minutes. as a result, the teacher performs a two - tailed hypothesis test with a significance level of 5%. which conclusion is valid based on the results of the test?\no her students, on average, do not take 30 minutes on the quiz, contrary to what the textbook company stated.\no the teacher should pick up all unfinished quizzes at 25 minutes because her students are so much faster than average.\no the teacher does not have enough information to make a conclusion about the average time on the test.\no her students, on average, do take the 30 minutes as the textbook company stated.

Answer

Explanation:

Step1: Identificar hipótesis nula y alternativa

Hipótesis nula $H_0: \mu = 30$, hipótesis alternativa $H_1: \mu\neq30$

Step2: Calcular la estadística de prueba

La fórmula para la estadística de prueba en una prueba de media con desviación estándar conocida es $z=\frac{\bar{x}-\mu}{\frac{\sigma}{\sqrt{n}}}$, donde $\bar{x} = 25$, $\mu = 30$, $\sigma = 3$ y $n = 10$. $z=\frac{25 - 30}{\frac{3}{\sqrt{10}}}=\frac{- 5}{\frac{3}{\sqrt{10}}}\approx - 5.27$

Step3: Encontrar los valores críticos

Para un nivel de significancia de $\alpha=0.05$ en una prueba bilateral, los valores críticos son $z_{\alpha/2}=\pm1.96$

Step4: Tomar una decisión

Como $z\approx - 5.27<-1.96$, rechazamos la hipótesis nula.

Answer:

Her students, on average, do not take 30 minutes on the quiz, contrary to what the textbook company stated.