the theoretical probability of a couple having a baby girl is $\frac{1}{2}$. what is $p(\text{girl}…

the theoretical probability of a couple having a baby girl is $\frac{1}{2}$. what is $p(\text{girl}, \text{girl}, \text{girl})$?\n$\frac{1}{8}$\n$\frac{1}{6}$\n$\frac{1}{3}$\n$\frac{3}{8}$

the theoretical probability of a couple having a baby girl is $\frac{1}{2}$. what is $p(\text{girl}, \text{girl}, \text{girl})$?\n$\frac{1}{8}$\n$\frac{1}{6}$\n$\frac{1}{3}$\n$\frac{3}{8}$

Answer

Explanation:

Step1: Identify independent events

The events of having a girl in each birth are independent.

Step2: Apply probability - multiplication rule

For independent events (A), (B), and (C), (P(A\cap B\cap C)=P(A)\times P(B)\times P(C)). Here, (P(\text{girl})=\frac{1}{2}) for each birth. So (P(\text{girl},\text{girl},\text{girl})=\frac{1}{2}\times\frac{1}{2}\times\frac{1}{2}).

Step3: Calculate the result

(\frac{1}{2}\times\frac{1}{2}\times\frac{1}{2}=\frac{1}{8})

Answer:

A. (\frac{1}{8})