the theoretical probability of a couple having a baby girl is $\frac{1}{2}$. what is $p(\text{girl}…

the theoretical probability of a couple having a baby girl is $\frac{1}{2}$. what is $p(\text{girl}, \text{girl}, \text{girl})$?\n$\frac{1}{8}$\n$\frac{1}{6}$\n$\frac{1}{3}$\n$\frac{3}{8}$
Answer
Explanation:
Step1: Identify independent events
The events of having a girl in each birth are independent.
Step2: Apply probability - multiplication rule
For independent events (A), (B), and (C), (P(A\cap B\cap C)=P(A)\times P(B)\times P(C)). Here, (P(\text{girl})=\frac{1}{2}) for each birth. So (P(\text{girl},\text{girl},\text{girl})=\frac{1}{2}\times\frac{1}{2}\times\frac{1}{2}).
Step3: Calculate the result
(\frac{1}{2}\times\frac{1}{2}\times\frac{1}{2}=\frac{1}{8})
Answer:
A. (\frac{1}{8})