thirty - two percent of families residing in a rural, farming town own a goat and 41% of families own a dog…

thirty - two percent of families residing in a rural, farming town own a goat and 41% of families own a dog. twenty - four percent of families own both types of animals. if a family from this town is chosen at random, what is the probability that it owns either a goat or a dog? 0.15 0.33 0.49 0.97

thirty - two percent of families residing in a rural, farming town own a goat and 41% of families own a dog. twenty - four percent of families own both types of animals. if a family from this town is chosen at random, what is the probability that it owns either a goat or a dog? 0.15 0.33 0.49 0.97

Answer

Explanation:

Step1: Recall the formula for the probability of the union

We use the formula $P(A\cup B)=P(A)+P(B)-P(A\cap B)$. Let $A$ be the event of owning a goat and $B$ be the event of owning a dog.

Step2: Identify the given probabilities

We are given that $P(A) = 0.32$, $P(B)=0.41$ and $P(A\cap B)=0.24$.

Step3: Substitute the values into the formula

$P(A\cup B)=0.32 + 0.41- 0.24$. $P(A\cup B)=0.49$.

Answer:

C. 0.49