three coins are tossed in succession. what is the probability of heads-tails-heads?\n\n1/2\n1/8\n1/6

Explanation:

Step1: Determine probability for a single coin toss

The probability of getting heads ($H$) or tails ($T$) in one toss is $P(H) = P(T) = \frac{1}{2}$.

Step2: Identify the specific sequence required

The problem asks for the specific sequence: Heads, then Tails, then Heads ($H-T-H$).

Step3: Calculate the joint probability of independent events

Since each toss is independent, multiply the individual probabilities: $$P(H, T, H) = P(H) \times P(T) \times P(H)$$ $$P(H, T, H) = \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2}$$

Step4: Perform the multiplication

$$P(H, T, H) = \frac{1}{8}$$

Answer:

1/8