three out of seven students in the cafeteria line are chosen to answer survey questions. how many different…

three out of seven students in the cafeteria line are chosen to answer survey questions. how many different combinations of three students are possible? 7c3 = 7! / (7 - 3)!3! 7 35 70 210

three out of seven students in the cafeteria line are chosen to answer survey questions. how many different combinations of three students are possible? 7c3 = 7! / (7 - 3)!3! 7 35 70 210

Answer

Explanation:

Step1: Recall combination formula

The combination formula is ${n}C{r}=\frac{n!}{(n - r)!r!}$, where $n$ is the total number of items, and $r$ is the number of items to be chosen. Here $n = 7$ and $r=3$.

Step2: Calculate factorial values

$n!=7!=7\times6\times5\times4\times3\times2\times1$, $(n - r)!=(7 - 3)!=4!=4\times3\times2\times1$, $r!=3!=3\times2\times1$. Then ${7}C{3}=\frac{7!}{(7 - 3)!3!}=\frac{7\times6\times5\times4!}{4!\times3\times2\times1}$.

Step3: Simplify the expression

The $4!$ terms in the numerator and denominator cancel out. We get $\frac{7\times6\times5}{3\times2\times1}=\frac{210}{6}=35$.

Answer:

B. 35