three out of seven students in the cafeteria line are chosen to answer survey questions. how many different…

three out of seven students in the cafeteria line are chosen to answer survey questions. how many different combinations of three students are possible? 7c3 = 7! / (7 - 3)!3! 7 35 70 210
Answer
Explanation:
Step1: Recall combination formula
The combination formula is ${n}C{r}=\frac{n!}{(n - r)!r!}$, where $n$ is the total number of items, and $r$ is the number of items to be chosen. Here $n = 7$ and $r=3$.
Step2: Calculate factorial values
$n!=7!=7\times6\times5\times4\times3\times2\times1$, $(n - r)!=(7 - 3)!=4!=4\times3\times2\times1$, $r!=3!=3\times2\times1$. Then ${7}C{3}=\frac{7!}{(7 - 3)!3!}=\frac{7\times6\times5\times4!}{4!\times3\times2\times1}$.
Step3: Simplify the expression
The $4!$ terms in the numerator and denominator cancel out. We get $\frac{7\times6\times5}{3\times2\times1}=\frac{210}{6}=35$.
Answer:
B. 35