2.2: tomato plants: histogram\na histogram can be used to represent the distribution of numerical data.\n1…

2.2: tomato plants: histogram\na histogram can be used to represent the distribution of numerical data.\n1. the data represent the number of days it takes for different tomato plants to produce tomatoes. use the information to complete the frequency table.\n47 52 58 55 59 62 62 62 63 65 68\n66 65 68 69 72 73 76 75 72 73 79\n78 80 81 82 85 88 89 90\n\n| days to produce fruit | frequency |\n| ---- | ---- |\n| 40 - 50 | 1 |\n| 50 - 60 | 4 |\n| 60 - 70 | 9 |\n| 70 - 80 | 9 |\n| 80 - 90 | 6 |\n| 90 - 100 | 1 |\n\n2. use the set of axes and the information in your table to create a histogram.\n\nnumber of tomato plants\n30 40 50 60 70 80 90 100\ndays to produce fruit

2.2: tomato plants: histogram\na histogram can be used to represent the distribution of numerical data.\n1. the data represent the number of days it takes for different tomato plants to produce tomatoes. use the information to complete the frequency table.\n47 52 58 55 59 62 62 62 63 65 68\n66 65 68 69 72 73 76 75 72 73 79\n78 80 81 82 85 88 89 90\n\n| days to produce fruit | frequency |\n| ---- | ---- |\n| 40 - 50 | 1 |\n| 50 - 60 | 4 |\n| 60 - 70 | 9 |\n| 70 - 80 | 9 |\n| 80 - 90 | 6 |\n| 90 - 100 | 1 |\n\n2. use the set of axes and the information in your table to create a histogram.\n\nnumber of tomato plants\n30 40 50 60 70 80 90 100\ndays to produce fruit

Answer

Explanation:

Step1: Count data in ranges

For the range 40 - 50, there is 1 data point (47). For 50 - 60, there are 4 data - points (52, 58, 55, 59). For 60 - 70, count the values in this range from the data set to get 9. For 70 - 80, count to get 9. For 80 - 90, count to get 6. For 90 - 100, there is 1 data point (90).

Step2: Create histogram

On the x - axis, label the intervals (days to produce fruit: 40 - 50, 50 - 60, 60 - 70, 70 - 80, 80 - 90, 90 - 100). On the y - axis, label the number of tomato plants. Draw bars with heights corresponding to the frequencies in each interval. The bar for 40 - 50 has height 1, for 50 - 60 has height 4, for 60 - 70 has height 9, for 70 - 80 has height 9, for 80 - 90 has height 6, and for 90 - 100 has height 1.

Answer:

The frequency table is completed as shown in the problem statement (40 - 50: 1, 50 - 60: 4, 60 - 70: 9, 70 - 80: 9, 80 - 90: 6, 90 - 100: 1) and the histogram is drawn as described above.