tony rides his bike to school. this morning, he was running late, so he biked very quickly. he stayed at…

Explanation:

Step1: Analyze first segment (to school)

Tony starts at home (distance = 0 km) and bikes quickly to school. On a distance-time graph, this is a steep upward-sloping line (high speed = steep slope) going from (0, 0) to a positive distance value.

Step2: Analyze second segment (at school)

Tony stays at school for hours, so his distance from home does not change. This is a horizontal line (slope = 0) at the constant distance of the school from home.

Step3: Analyze third segment (return home)

Tony bikes home at a normal pace, which is slower than his morning speed. On the graph, this is a downward-sloping line with a less steep slope than the first segment, going from the school's distance back to 0 km.

Step4: Match to graphs

Only the bottom-left graph has: a steep upward slope from 0, a flat horizontal segment, and a less steep downward slope back to 0. The top-left graph has an overly steep downward slope (faster than the trip to school, which contradicts the "normal pace" return), the top-right graph starts at a non-zero distance and ends at a high distance (wrong direction), and the bottom-right graph starts at a non-zero distance and has no flat segment (no time at school).

Answer:

The bottom-left graph (with a steep upward line, flat horizontal line, and moderately steep downward line)