a b total\nc x 0.25 g\nd y 0.68 h\ne z 0.07 j\ntotal 1.0 1.0 1.0\nwhich value for y in the table would be…

a b total\nc x 0.25 g\nd y 0.68 h\ne z 0.07 j\ntotal 1.0 1.0 1.0\nwhich value for y in the table would be least likely to indicate an association between the variables?\n0.06\n0.24\n0.69\n1.0

a b total\nc x 0.25 g\nd y 0.68 h\ne z 0.07 j\ntotal 1.0 1.0 1.0\nwhich value for y in the table would be least likely to indicate an association between the variables?\n0.06\n0.24\n0.69\n1.0

Answer

Explanation:

Step1: Recall the concept of independence

In a two - way table, if the variables are independent, the joint probabilities follow the rule (P(A\cap B)=P(A)\times P(B)). When the values in the table suggest independence, there is no association between the variables. For the columns (A) and (B) with total probabilities of (1.0) each, and rows (C), (D), (E), we want the distribution of values in the rows to be similar to the distribution in the columns if there is no association.

Step2: Analyze the given values in column (B)

The values in column (B) are (0.25), (0.68), and (0.07). If there is no association, the values in column (A) should have a similar relative distribution. The sum of the values in column (B) is (0.25 + 0.68+0.07=1.0).

Step3: Consider the balance of values

We want the value of (Y) to be such that the distribution of values in row (D) is in line with the overall distribution. If (Y = 0.24), the distribution of values in row (D) will be more in line with the distribution of values in the other rows and columns compared to the other options. When (Y = 0.06), it is too small compared to the other non - (Y) values in the table. When (Y=0.69), it is too large and disrupts the balance. When (Y = 1.0), it completely changes the nature of the distribution in row (D).

Answer:

0.24