two number cubes are rolled. what is the probability that the first lands on 6 and the second lands on an…

Answer:

$\frac{1}{12}$

Explanation:

Step1: Find probability of first cube landing on 6

A number - cube has 6 faces. The probability of the first cube landing on 6 is $P(6)=\frac{1}{6}$.

Step2: Find probability of second cube landing on odd number

The odd numbers on a number - cube are 1, 3, 5. So there are 3 odd numbers out of 6. The probability of the second cube landing on an odd number is $P(\text{odd})=\frac{3}{6}=\frac{1}{2}$.

Step3: Use multiplication rule for independent events

Since the two rolls are independent events, the probability that the first lands on 6 and the second lands on an odd number is $P = P(6)\times P(\text{odd})=\frac{1}{6}\times\frac{1}{2}=\frac{1}{12}$.