the two - way table shows the number of sport utility vehicles with certain features for sale at the car…

the two - way table shows the number of sport utility vehicles with certain features for sale at the car lot.\n| | 4 - wheel drive | no 4 - wheel drive | total |\n|--|--|--|--|\n| third - row seats | 18 | 12 | 30 |\n| no third - row seats | 7 | 28 | 35 |\n| total | 25 | 40 | 65 |\nwhat is the probability that a randomly selected car with no 4 - wheel drive has third - row seats?\no 0.3\no 0.4\no 0.7\no 0.8

the two - way table shows the number of sport utility vehicles with certain features for sale at the car lot.\n| | 4 - wheel drive | no 4 - wheel drive | total |\n|--|--|--|--|\n| third - row seats | 18 | 12 | 30 |\n| no third - row seats | 7 | 28 | 35 |\n| total | 25 | 40 | 65 |\nwhat is the probability that a randomly selected car with no 4 - wheel drive has third - row seats?\no 0.3\no 0.4\no 0.7\no 0.8

Answer

Explanation:

Step1: Identify relevant values

The number of cars with no 4 - wheel drive and third - row seats is 12, and the total number of cars with no 4 - wheel drive is 40.

Step2: Calculate probability

The probability formula for conditional probability in this case is $P=\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}$. So $P=\frac{12}{40}$.

Step3: Simplify the fraction

$\frac{12}{40}=\frac{3}{10}=0.3$

Answer:

0.3