type the correct answer in the box. for this item, any non - integer answer should be entered as a decimal…

type the correct answer in the box. for this item, any non - integer answer should be entered as a decimal rounded to the hundredths place. statistics show that a certain soccer player has a 63% chance of missing the goal each time he shoots. if this player shoots twice, the probability that he scores a goal both times is %.
Answer
Explanation:
Step1: Find the probability of scoring a goal once
The probability of missing a goal is 63% or 0.63. The probability of scoring a goal in a single - shot, $p$, is $1 - 0.63=0.37$.
Step2: Use the multiplication rule for independent events
Since the two shots are independent events, the probability of scoring a goal both times is $p\times p$. Substitute $p = 0.37$ into the formula, we get $0.37\times0.37 = 0.1369$.
Step3: Convert to percentage and round
To convert to a percentage, multiply by 100: $0.1369\times100 = 13.69%$. Rounding to the hundredths place, the result is 13.69.
Answer:
13.69