type the correct answer in the box. use numerals instead of words. if necessary, use / for the fraction bar…

type the correct answer in the box. use numerals instead of words. if necessary, use / for the fraction bar. the mean of a population being sampled is 64, and the standard deviation is 6. if the sample size is 50, the standard error of the mean is (round off your answer to the nearest hundredth.)

type the correct answer in the box. use numerals instead of words. if necessary, use / for the fraction bar. the mean of a population being sampled is 64, and the standard deviation is 6. if the sample size is 50, the standard error of the mean is (round off your answer to the nearest hundredth.)

Answer

Explanation:

Step1: Recall the formula for standard error of the mean

The formula for the standard error of the mean ($SE$) is $SE=\frac{\sigma}{\sqrt{n}}$, where $\sigma$ is the population standard - deviation and $n$ is the sample size.

Step2: Identify the values of $\sigma$ and $n$

We are given that $\sigma = 6$ and $n = 50$.

Step3: Substitute the values into the formula

$SE=\frac{6}{\sqrt{50}}$. We know that $\sqrt{50}\approx7.071$. Then $SE=\frac{6}{7.071}\approx0.85$.

Answer:

$0.85$