type the correct answer in the box. use numerals instead of words. if necessary, use / for the fraction bar…

type the correct answer in the box. use numerals instead of words. if necessary, use / for the fraction bar. malik randomly picked two different numbers from 1 to 9 (including 1 and 9). the first of the two numbers he picks is odd. what is the probability that malik picked a second odd number, given that the first number was odd?

type the correct answer in the box. use numerals instead of words. if necessary, use / for the fraction bar. malik randomly picked two different numbers from 1 to 9 (including 1 and 9). the first of the two numbers he picks is odd. what is the probability that malik picked a second odd number, given that the first number was odd?

Answer

Explanation:

Step1: Identify odd - numbers from 1 - 9

The odd numbers from 1 to 9 are 1, 3, 5, 7, 9. So there are 5 odd numbers.

Step2: Calculate the conditional - probability

Since the first number is odd, for the second - pick, there are 8 remaining numbers (because the two numbers are different), and 4 of them are odd. The probability formula for conditional probability in this case is (P=\frac{\text{Number of favorable outcomes}}{\text{Number of total outcomes}}). So the probability that the second number is odd given that the first number is odd is (\frac{4}{8}=\frac{1}{2}).

Answer:

(\frac{1}{2})