type in the five - number summary for the data shown on the right. the minimum of the data is . the first…

Answer:

The minimum of the data is 81. The first quartile is 93. The median of the data is 104. The third quartile is 115. The maximum of the data is 136.

Explanation:

Step1: Write out data set

81, 83, 90, 93, 97, 104, 104, 107, 109, 111, 113, 115, 125, 129, 129, 132, 136

Step2: Find minimum

The smallest value is 81.

Step3: Calculate position of Q1

$n = 17$, $position_{Q1}=\frac{1}{4}(n + 1)=\frac{1}{4}(17+ 1)=4.5$. Interpolate between 4th and 5th ordered - values. 4th value is 93, 5th value is 97. $Q1=93+(97 - 93)\times0.5 = 93$.

Step4: Find median

$position_{median}=\frac{n + 1}{2}=\frac{17+1}{2}=9$. 9th value is 104.

Step5: Calculate position of Q3

$position_{Q3}=\frac{3}{4}(n + 1)=\frac{3}{4}(17 + 1)=13.5$. Interpolate between 13th and 14th ordered - values. 13th value is 115, 14th value is 125. $Q3=115+(125 - 115)\times0.5 = 115$.

Step6: Find maximum

The largest value is 136.