for a 4 - units class like statistics, students should spend average of 12 hours studying for the class. a…

for a 4 - units class like statistics, students should spend average of 12 hours studying for the class. a survey was done on 23 students, and the distribution of total study hours per week is bell - shaped with a mean of 14 hours and a standard deviation of 3 hours. use the empirical rule to answer the following questions. a) 68% of the students spend between hours and hours on statistics each week. b) 95% of the students spend between hours and hours on statistics each week. c) 99.7% of the students spend between hours and hours on statistics each week.

for a 4 - units class like statistics, students should spend average of 12 hours studying for the class. a survey was done on 23 students, and the distribution of total study hours per week is bell - shaped with a mean of 14 hours and a standard deviation of 3 hours. use the empirical rule to answer the following questions. a) 68% of the students spend between hours and hours on statistics each week. b) 95% of the students spend between hours and hours on statistics each week. c) 99.7% of the students spend between hours and hours on statistics each week.

Answer

Explanation:

Step1: Recall the Empirical Rule

The Empirical Rule for a normal - distribution states that about 68% of the data lies within 1 standard deviation of the mean, about 95% lies within 2 standard deviations of the mean, and about 99.7% lies within 3 standard deviations of the mean. The mean $\mu = 12$ hours and the standard deviation $\sigma=3$ hours.

Step2: Calculate bounds for 68%

For 68% of the data, the lower bound is $\mu-\sigma$ and the upper - bound is $\mu + \sigma$. $\mu-\sigma=12 - 3=9$ $\mu+\sigma=12 + 3=15$

Step3: Calculate bounds for 95%

For 95% of the data, the lower bound is $\mu - 2\sigma$ and the upper - bound is $\mu+2\sigma$. $\mu - 2\sigma=12-2\times3=12 - 6 = 6$ $\mu+2\sigma=12 + 2\times3=12 + 6=18$

Step4: Calculate bounds for 99.7%

For 99.7% of the data, the lower bound is $\mu - 3\sigma$ and the upper - bound is $\mu+3\sigma$. $\mu - 3\sigma=12-3\times3=12 - 9 = 3$ $\mu+3\sigma=12 + 3\times3=12 + 9=21$

Answer:

a) 9 hours and 15 hours b) 6 hours and 18 hours c) 3 hours and 21 hours