use the data in the following table, which lists drive - thru order accuracy at popular fast food chains…

use the data in the following table, which lists drive - thru order accuracy at popular fast food chains. assume that orders are randomly selected from those included in the table.\ndrive - thru restaurant\n| | a | b | c | d |\n|--|--|--|--|--| \n| order accurate | 335 | 261 | 247 | 147 |\n| order not accurate | 30 | 56 | 33 | 19 |\nif one order is selected, find the probability of getting an order that is not accurate or is from restaurant c. are the events of selecting an order that is not accurate and selecting an order from restaurant c disjoint events?\nthe probability of getting an order from restaurant c or an order that is not accurate is 0.341. (round to three decimal places as needed.)\nare the events of selecting an order from restaurant c and selecting an inaccurate order disjoint events?\nthe events are not disjoint because it is not possible to pick an accurate order.

use the data in the following table, which lists drive - thru order accuracy at popular fast food chains. assume that orders are randomly selected from those included in the table.\ndrive - thru restaurant\n| | a | b | c | d |\n|--|--|--|--|--| \n| order accurate | 335 | 261 | 247 | 147 |\n| order not accurate | 30 | 56 | 33 | 19 |\nif one order is selected, find the probability of getting an order that is not accurate or is from restaurant c. are the events of selecting an order that is not accurate and selecting an order from restaurant c disjoint events?\nthe probability of getting an order from restaurant c or an order that is not accurate is 0.341. (round to three decimal places as needed.)\nare the events of selecting an order from restaurant c and selecting an inaccurate order disjoint events?\nthe events are not disjoint because it is not possible to pick an accurate order.

Answer

Explanation:

Step1: Calculate total number of orders

Total orders = $(335 + 261+247 + 147)+(30 + 56+33 + 19)=1128$

Step2: Calculate number of non - accurate orders

Non - accurate orders = $30 + 56+33 + 19 = 138$

Step3: Calculate number of orders from Restaurant C

Orders from Restaurant C = $247+33 = 280$

Step4: Calculate number of non - accurate orders from Restaurant C

Non - accurate orders from Restaurant C = 33

Step5: Use the addition rule for probability

$P(\text{not accurate or from C})=P(\text{not accurate})+P(\text{from C})-P(\text{not accurate and from C})$ $P(\text{not accurate})=\frac{138}{1128}$, $P(\text{from C})=\frac{280}{1128}$, $P(\text{not accurate and from C})=\frac{33}{1128}$ $P(\text{not accurate or from C})=\frac{138 + 280-33}{1128}=\frac{385}{1128}\approx0.341$

Step6: Determine if events are disjoint

Disjoint events cannot occur at the same time. Since there are non - accurate orders from Restaurant C (33 non - accurate orders from C), it is possible for an order to be non - accurate and from Restaurant C. So the events are not disjoint.

Answer:

The probability of getting an order that is not accurate or is from Restaurant C is approximately $0.341$. The events of selecting an order that is not accurate and selecting an order from Restaurant C are not disjoint.