use the data in the following table, which lists drive - thru order accuracy at popular fast food chains…

use the data in the following table, which lists drive - thru order accuracy at popular fast food chains. assume that orders are randomly selected from those included in the table.\ndrive - thru restaurant\n| | a | b | c | d |\n|--|--|--|--|--|\n| order accurate | 317 | 272 | 233 | 131 |\n| order not accurate | 36 | 60 | 39 | 19 |\nif one order is selected, find the probability of getting food that is not from restaurant a.\nthe probability of getting food that is not from restaurant a is \n(round to three decimal places as needed.)
Answer
Explanation:
Step1: Calculate total number of orders
Sum up all values in the table. $317 + 272+233 + 131+36+60+39+19=(317 + 36)+(272+60)+(233 + 39)+(131+19)=353+332+272+150 = 1107$
Step2: Calculate number of orders from Restaurant A
Sum up accurate and not - accurate orders from Restaurant A. $317+36 = 353$
Step3: Calculate number of orders not from Restaurant A
Subtract number of orders from Restaurant A from total number of orders. $1107 - 353=754$
Step4: Calculate the probability
Probability = $\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}$. $P=\frac{754}{1107}\approx0.681$
Answer:
$0.681$