use the data in the following table, which lists drive - thru order accuracy at popular fast food chains…

use the data in the following table, which lists drive - thru order accuracy at popular fast food chains. assume that orders are randomly selected from those included in the table\ndrive - thru restaurant \n| | a | b | c | d |\n|--|--|--|--|--| \n| order accurate | 336 | 262 | 233 | 121 |\n| order not accurate | 31 | 55 | 33 | 15 |\nif one order is selected, find the probability of getting food that is not from restaurant a.\nthe probability of getting food that is not from restaurant a is \n(round to three decimal places as needed.)

use the data in the following table, which lists drive - thru order accuracy at popular fast food chains. assume that orders are randomly selected from those included in the table\ndrive - thru restaurant \n| | a | b | c | d |\n|--|--|--|--|--| \n| order accurate | 336 | 262 | 233 | 121 |\n| order not accurate | 31 | 55 | 33 | 15 |\nif one order is selected, find the probability of getting food that is not from restaurant a.\nthe probability of getting food that is not from restaurant a is \n(round to three decimal places as needed.)

Answer

Explanation:

Step1: Calculate total number of orders

$336 + 262+233 + 121+31+55+33+15=(336 + 31)+(262 + 55)+(233+33)+(121 + 15)=367+317+266+136 = 1086$

Step2: Calculate number of orders not from Restaurant A

$262+233 + 121+55+33+15=(262+55)+(233+33)+(121 + 15)=317+266+136 = 719$

Step3: Calculate the probability

Probability = $\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}=\frac{719}{1086}\approx 0.662$

Answer:

$0.662$