use the display of data to find the standard deviation.\nthe standard deviation is approximately \n(do not…

use the display of data to find the standard deviation.\nthe standard deviation is approximately \n(do not round until the final answer. then round to the nearest hundredth as needed.)
Answer
Explanation:
Step1: Calculate the mean
First, find the mid - points of each class. Let (x) be the mid - point and (f) be the frequency. The mid - points are (x_1 = 7), (x_2=8), (x_3 = 9) with frequencies (f_1 = 4), (f_2=7), (f_3 = 4) respectively. The total frequency (n=f_1 + f_2+f_3=4 + 7+4=15). The mean (\bar{x}=\frac{\sum_{i = 1}^{3}f_ix_i}{n}=\frac{4\times7 + 7\times8+4\times9}{15}=\frac{28 + 56+36}{15}=\frac{120}{15}=8).
Step2: Calculate the squared differences
Calculate ((x_i-\bar{x})^2) for each (i). For (x_1 = 7), ((7 - 8)^2=1); for (x_2 = 8), ((8 - 8)^2=0); for (x_3 = 9), ((9 - 8)^2=1).
Step3: Calculate the weighted squared differences
Calculate (f_i(x_i-\bar{x})^2) for each (i). (f_1(x_1-\bar{x})^2=4\times1 = 4), (f_2(x_2-\bar{x})^2=7\times0 = 0), (f_3(x_3-\bar{x})^2=4\times1 = 4).
Step4: Calculate the variance
The variance (s^2=\frac{\sum_{i = 1}^{3}f_i(x_i-\bar{x})^2}{n - 1}=\frac{4+0 + 4}{15 - 1}=\frac{8}{14}\approx0.5714).
Step5: Calculate the standard deviation
The standard deviation (s=\sqrt{s^2}=\sqrt{\frac{8}{14}}\approx0.76).
Answer:
0.76