use the display of data to find the standard deviation.\nthe standard deviation is approximately \n(do not…

use the display of data to find the standard deviation.\nthe standard deviation is approximately \n(do not round until the final answer. then round to the nearest hundredth as needed.)

use the display of data to find the standard deviation.\nthe standard deviation is approximately \n(do not round until the final answer. then round to the nearest hundredth as needed.)

Answer

Explanation:

Step1: Calculate the mean

First, find the mid - points of each class. Let (x) be the mid - point and (f) be the frequency. The mid - points are (x_1 = 7), (x_2=8), (x_3 = 9) with frequencies (f_1 = 4), (f_2=7), (f_3 = 4) respectively. The total frequency (n=f_1 + f_2+f_3=4 + 7+4=15). The mean (\bar{x}=\frac{\sum_{i = 1}^{3}f_ix_i}{n}=\frac{4\times7 + 7\times8+4\times9}{15}=\frac{28 + 56+36}{15}=\frac{120}{15}=8).

Step2: Calculate the squared differences

Calculate ((x_i-\bar{x})^2) for each (i). For (x_1 = 7), ((7 - 8)^2=1); for (x_2 = 8), ((8 - 8)^2=0); for (x_3 = 9), ((9 - 8)^2=1).

Step3: Calculate the weighted squared differences

Calculate (f_i(x_i-\bar{x})^2) for each (i). (f_1(x_1-\bar{x})^2=4\times1 = 4), (f_2(x_2-\bar{x})^2=7\times0 = 0), (f_3(x_3-\bar{x})^2=4\times1 = 4).

Step4: Calculate the variance

The variance (s^2=\frac{\sum_{i = 1}^{3}f_i(x_i-\bar{x})^2}{n - 1}=\frac{4+0 + 4}{15 - 1}=\frac{8}{14}\approx0.5714).

Step5: Calculate the standard deviation

The standard deviation (s=\sqrt{s^2}=\sqrt{\frac{8}{14}}\approx0.76).

Answer:

0.76